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.5x^2+2.5x-1.5=0
a = .5; b = 2.5; c = -1.5;
Δ = b2-4ac
Δ = 2.52-4·.5·(-1.5)
Δ = 9.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2.5)-\sqrt{9.25}}{2*.5}=\frac{-2.5-\sqrt{9.25}}{1} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2.5)+\sqrt{9.25}}{2*.5}=\frac{-2.5+\sqrt{9.25}}{1} $
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